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October 04, 2005, at 12:29 PM MST by Tau Zero -
Changed line 48 from:

Back of the envelope calcs: to reach 1/4 c (quarter light speed) at 1 g (earth gravity, typical hard sci-fi acceleration), you'd only need about 88 days. (http://www.google.com/search?hl=en&lr=&safe=off&rls=GGLD%2CGGLD%3A2005-13%2CGGLD%3Aen&q=.25+*+speed+of+light+%2F+9.81+m%2Fs%5E2%29 calculation) So, speed up to 1/4 c, slow down at end, you only add at most 176 days, or about 0.5 years. Reasonable, given fancy drive that can sustain acceleration (i.e. firefly drive), but don't need inertial dampening. By the way, the rotating jets would on firefly would work great to maintain 1 g acceleration and give gravity oriented properly for the passengers. Of course, the tail seems to be where the major engine is.

to:

Back of the envelope calcs: to reach 1/4 c (quarter light speed) at 1 g (earth gravity, typical hard sci-fi acceleration), you'd only need about 88 days. http://www.google.com/search?hl=en&lr=&safe=off&rls=GGLD%2CGGLD%3A2005-13%2CGGLD%3Aen&q=.25+*+speed+of+light+%2F+9.81+m%2Fs%5E2%29 calculation So, speed up to 1/4 c, slow down at end, you only add at most 176 days, or about 0.5 years. Reasonable, given fancy drive that can sustain acceleration (i.e. firefly drive), but don't need inertial dampening. By the way, the rotating jets would on firefly would work great to maintain 1 g acceleration and give gravity oriented properly for the passengers. Of course, the tail seems to be where the major engine is.

October 04, 2005, at 12:29 PM MST by Tau Zero -
Changed line 48 from:

Back of the envelope calcs: to reach 1/4 c (quarter light speed) at 1 g (earth gravity, typical hard sci-fi acceleration), you'd only need about 88 days. (http://www.google.com/search?hl=en&lr=&safe=off&rls=GGLD%2CGGLD%3A2005-13%2CGGLD%3Aen&q=.25+*+speed+of+light+%2F+9.81+m%2Fs%5E2%29) So, speed up to 1/4 c, slow down at end, you only add at most 176 days, or about 0.5 years. Reasonable, given fancy drive that can sustain acceleration (i.e. firefly drive), but don't need inertial dampening. By the way, the rotating jets would on firefly would work great to maintain 1 g acceleration and give gravity oriented properly for the passengers. Of course, the tail seems to be where the major engine is.

to:

Back of the envelope calcs: to reach 1/4 c (quarter light speed) at 1 g (earth gravity, typical hard sci-fi acceleration), you'd only need about 88 days. (http://www.google.com/search?hl=en&lr=&safe=off&rls=GGLD%2CGGLD%3A2005-13%2CGGLD%3Aen&q=.25+*+speed+of+light+%2F+9.81+m%2Fs%5E2%29 calculation) So, speed up to 1/4 c, slow down at end, you only add at most 176 days, or about 0.5 years. Reasonable, given fancy drive that can sustain acceleration (i.e. firefly drive), but don't need inertial dampening. By the way, the rotating jets would on firefly would work great to maintain 1 g acceleration and give gravity oriented properly for the passengers. Of course, the tail seems to be where the major engine is.

October 04, 2005, at 12:26 PM MST by Tau Zero -
Added lines 46-48:

Back of the envelope calcs: to reach 1/4 c (quarter light speed) at 1 g (earth gravity, typical hard sci-fi acceleration), you'd only need about 88 days. (http://www.google.com/search?hl=en&lr=&safe=off&rls=GGLD%2CGGLD%3A2005-13%2CGGLD%3Aen&q=.25+*+speed+of+light+%2F+9.81+m%2Fs%5E2%29) So, speed up to 1/4 c, slow down at end, you only add at most 176 days, or about 0.5 years. Reasonable, given fancy drive that can sustain acceleration (i.e. firefly drive), but don't need inertial dampening. By the way, the rotating jets would on firefly would work great to maintain 1 g acceleration and give gravity oriented properly for the passengers. Of course, the tail seems to be where the major engine is.

September 28, 2005, at 11:03 AM MST by SomeGuy -
Changed line 40 from:

Now, I've no idea what affect Time Dilation (what happens when you travel at speeds approaching the speed of light) would have on this, but I believe it stands as a good theory as to the size of the Firefly Universe, and how we got there...

to:

Now, I've no idea what effect Time Dilation (what happens when you travel at speeds approaching the speed of light) would have on this, but I believe it stands as a good theory as to the size of the Firefly Universe, and how we got there...

September 27, 2005, at 10:10 PM MST by Scotti -
Changed line 40 from:

Now, I've no idea what affect Time Dilation (what happens when you travel at speeds approaching the speed of light) would have on this, but I beleive it stands as a good theory as to the size of the Firefly Universe, and how we got there...

to:

Now, I've no idea what affect Time Dilation (what happens when you travel at speeds approaching the speed of light) would have on this, but I believe it stands as a good theory as to the size of the Firefly Universe, and how we got there...

August 07, 2005, at 11:58 AM MST by DPK -
Added lines 44-45:

However, all of these scenarios ignore the acceleration time. It takes time to get up to speed, and unfortunately, the only engines we have concieved of that are efficient enough to allow intersteller travel also have extremely low accelerations. So the transit time will be far greater then what is shown here.

July 24, 2005, at 12:24 PM MST by DPK -
Changed line 42 from:

A relativistic correction for time is easily solved for. the change in experienced time is equal to the change in original time divided by the Lorentz factor. The lorentz factor is the corrective formula applied to all relativistic calculations, the square root of 1 minus the velocity squared divided by the speed of light squared. If you were to attempt to plug this into a spreadsheet, the formula would be ((1-(B2^2/(9*10^16)))^0.5) In any case, for a travel time of 16.8 years to the Centauri system, the experienced time would be 16.26 years. Not much of a difference.

to:

A relativistic correction for time is easily solved for. the change in experienced time is equal to the change in original time divided by the Lorentz factor. The lorentz factor is the corrective formula applied to all relativistic calculations, the square root of 1 minus the velocity squared divided by the speed of light squared. If you were to attempt to plug this into a spreadsheet, the formula would be ((1-(velocity^2/(9*10^16)))^0.5) In any case, for a travel time of 16.8 years to the Centauri system, the experienced time would be 16.26 years. Not much of a difference.

July 24, 2005, at 12:23 PM MST by DPK -
Changed line 3 from:

If we had mastered a drive able to safely accelerate ships to one quarter the speed of light, it wouldn't take that long to get to Alpha Centauri. Especially in ext. hibernation. BTW, when I say distance, I mean estimated... And, this is only an example made to point out the ease with which earth's population could leave and arrive somewhere easily... also, imagine if they headed for a star cluster... where the entire cluster is no more than 10 or 20 lightyears across... a "minigalaxy"... you could start with one system and there'd be many more within 1 or 2 lightyears. earth is in the boondocks. So, don't bash me on the incorrect reporting of the distance to Alpha Centauri... it was only an example... and anyway, .15 LY is NOTHING.

to:

If we had mastered a drive able to safely accelerate ships to one quarter the speed of light, it wouldn't take that long to get to Alpha Centauri. Especially in ext. hibernation. BTW, when I say distance, I mean estimated... And, this is only an example made to point out the ease with which earth's population could leave and arrive somewhere easily... also, imagine if they headed for a star cluster... where the entire cluster is no more than 10 or 20 lightyears across... a "minigalaxy"... you could start with one system and there'd be many more within 1 or 2 lightyears. earth is in the boondocks. (Though the problem is is the conditions of a star cluster are hostile for human life in terms of radiation, and resource poor) So, don't bash me on the incorrect reporting of the distance to Alpha Centauri... it was only an example... and anyway, .15 LY is NOTHING.

Changed line 42 from:
A relativistic correction for time is easily solved for. the change in experienced time is equal to the change in original time divided by the Lorentz factor. The lorentz factor is the corrective formula applied to all relativistic calculations, the square root of 1 minus the velocity squared divided by the speed of light squared. If you were to attempt to plug this into a spreadsheet, the formula would be ((1-(B2^2/(9*10^16)))^0.5) In any case, for a travel time of 16.8 years to the Centauri system, the experienced time would be 16.26 years. Not much of a difference.
to:

A relativistic correction for time is easily solved for. the change in experienced time is equal to the change in original time divided by the Lorentz factor. The lorentz factor is the corrective formula applied to all relativistic calculations, the square root of 1 minus the velocity squared divided by the speed of light squared. If you were to attempt to plug this into a spreadsheet, the formula would be ((1-(B2^2/(9*10^16)))^0.5) In any case, for a travel time of 16.8 years to the Centauri system, the experienced time would be 16.26 years. Not much of a difference.

July 24, 2005, at 12:21 PM MST by DPK -
Changed lines 40-44 from:

Now, I've no idea what affect Time Dilation (what happens when you travel at speeds approaching the speed of light) would have on this, but I beleive it stands as a good theory as to the size of the Firefly Universe, and how we got there...

to:

Now, I've no idea what affect Time Dilation (what happens when you travel at speeds approaching the speed of light) would have on this, but I beleive it stands as a good theory as to the size of the Firefly Universe, and how we got there...

A relativistic correction for time is easily solved for. the change in experienced time is equal to the change in original time divided by the Lorentz factor. The lorentz factor is the corrective formula applied to all relativistic calculations, the square root of 1 minus the velocity squared divided by the speed of light squared. If you were to attempt to plug this into a spreadsheet, the formula would be ((1-(B2^2/(9*10^16)))^0.5) In any case, for a travel time of 16.8 years to the Centauri system, the experienced time would be 16.26 years. Not much of a difference.
May 28, 2005, at 01:34 AM MST by MikeChance -
Changed line 40 from:

Now, I've no idea what affect Time Dilation would have on this, but I beleive it stands as a good theory as to the size of the Firefly Universe, and how we got there...

to:

Now, I've no idea what affect Time Dilation (what happens when you travel at speeds approaching the speed of light) would have on this, but I beleive it stands as a good theory as to the size of the Firefly Universe, and how we got there...

May 28, 2005, at 01:33 AM MST by MikeChance -
Changed lines 20-21 from:

FOR COMPARISON, the speed of sound at Sea Level (yes, it's different at different altitudes): speed of sound: 340.29 m/s (AKA MACH 1)

to:

FOR COMPARISON, the speed of sound at Sea Level (yes, it's different at different altitudes)
Speed of Sound: 340.29 m/s (AKA MACH 1)

May 28, 2005, at 01:32 AM MST by MikeChance -
Changed line 8 from:

SOL: 299,792,458 m/s (meters per second) (AKA a Lightsecond, as heard on Andromeda)

to:

SOL: 299,792,458 m/s (meters per second) (AKA a Lightsecond, as heard on Andromeda)\\

Changed line 11 from:

Distance to Alpha Centauri: 4.2 [or 4.36, but I used 4.2] Lightyears (lightyear = 1 year of travel at SOL)

to:

Distance to Alpha Centauri: 4.2 [or 4.36, but I used 4.2] Lightyears (lightyear = 1 year of travel at SOL)\\

Changed line 14 from:

(distance traveled @)SOL: 9,454,254,955,488,000 m/y (meters per year)

to:

(distance traveled @)SOL: 9,454,254,955,488,000 m/y (meters per year)\\

Changed line 17 from:

1/4 SOL: 2,363,563,738,872,000 m/y

to:

1/4 SOL: 2,363,563,738,872,000 m/y\\

Changed line 23 from:

MACH 1: 10,731,385,440 meters

to:

MACH 1: 10,731,385,440 meters\\

Changed line 26 from:

MACH 10: 107,313,854,400 m/y

to:

MACH 10: 107,313,854,400 m/y\\

Changed line 29 from:

MACH 20: 214,627,708,800 m/y

to:

MACH 20: 214,627,708,800 m/y\\

Changed line 32 from:

MACH 30: 321,941,563,200 m/y

to:

MACH 30: 321,941,563,200 m/y\\

Changed line 35 from:

MACH 100: 1,073,138,544,000 m/y

to:

MACH 100: 1,073,138,544,000 m/y\\

May 28, 2005, at 01:30 AM MST by MikeChance -
Changed lines 5-6 from:

REMEMBER, I USED METERS. NOT MILES. 1 Meter is equal to ABOUT 3.1 feet...

to:

Here are some very basic calculations: REMEMBER, I USED METERS. NOT MILES. 1 Meter is equal to ABOUT 3.1 feet. Also, when I say "AT", I mean "The time it would take to get there traveling at".

Deleted line 9:

distance to Alpha Centauri: 4.2 [or 4.36, but I used 4.2] Lightyears (lightyear = 1 year of travel at SOL)

Changed lines 11-12 from:

Distance to AC: 39,707,870,813,049,600 meters

to:

Distance to Alpha Centauri: 4.2 [or 4.36, but I used 4.2] Lightyears (lightyear = 1 year of travel at SOL) Alt. Distance to AC: 39,707,870,813,049,600 meters

Changed line 21 from:

speed of sound: 340.29 m/s (this is AKA MACH 1)

to:

speed of sound: 340.29 m/s (AKA MACH 1)

Added line 38:

37,000 years at merely Mach 100? Not bad... but nice to know it'll only take 16.8 @ a quarter the speed of light. I know what colony ship I'M riding on.

May 28, 2005, at 01:26 AM MST by MikeChance -
Changed line 1 from:

{{Mike Chance?}} Theory

to:

MikeChance's Theory

May 28, 2005, at 01:25 AM MST by MikeChance -
Changed line 1 from:
to:

{{Mike Chance?}} Theory

May 28, 2005, at 01:25 AM MST by MikeChance -
Changed line 1 from:
to:
May 28, 2005, at 01:24 AM MST by MikeChance -
Changed line 1 from:

MikeChance?'s Theory

to:
May 28, 2005, at 01:24 AM MST by MikeChance -
Changed line 1 from:

((Mike Chance?)) Theory

to:

MikeChance?'s Theory

May 28, 2005, at 01:23 AM MST by MikeChance -
Changed line 1 from:

((Mike Chance?))'s Theory

to:

((Mike Chance?)) Theory

May 28, 2005, at 01:23 AM MST by MikeChance -
Changed line 1 from:

Mike Chance? Theory:

to:

((Mike Chance?))'s Theory

Changed line 20 from:

speed of sound: 340.29 m/s (AKA MACH 1?)

to:

speed of sound: 340.29 m/s (this is AKA MACH 1)

May 28, 2005, at 01:21 AM MST by MikeChance -
Changed line 1 from:

Mike Chance?'s Theory:

to:

Mike Chance? Theory:

Changed line 3 from:

If we had mastered a drive able to safely accelerate ships to one quarter the speed of light(or So L?), it wouldn't take that long to get to Alpha Centauri. Especially in ext. hibernation. BTW, when I say distance, I mean estimated... And, this is only an example made to point out the ease with which earth's population could leave and arrive somewhere easily... also, imagine if they headed for a star cluster... where the entire cluster is no more than 10 or 20 lightyears across... a "minigalaxy"... you could start with one system and there'd be many more within 1 or 2 lightyears. earth is in the boondocks. So, don't bash me on the incorrect reporting of the distance to Alpha Centauri... it was only an example... and anyway, .15 LY is NOTHING.

to:

If we had mastered a drive able to safely accelerate ships to one quarter the speed of light, it wouldn't take that long to get to Alpha Centauri. Especially in ext. hibernation. BTW, when I say distance, I mean estimated... And, this is only an example made to point out the ease with which earth's population could leave and arrive somewhere easily... also, imagine if they headed for a star cluster... where the entire cluster is no more than 10 or 20 lightyears across... a "minigalaxy"... you could start with one system and there'd be many more within 1 or 2 lightyears. earth is in the boondocks. So, don't bash me on the incorrect reporting of the distance to Alpha Centauri... it was only an example... and anyway, .15 LY is NOTHING.

Changed lines 7-10 from:

So L?: 299,792,458 m/s (meters per second) (AKA a Lightsecond, as heard on Andromeda) 1/4 So L?: 74,948,114.5 m/s distance to Alpha Centauri: 4.2[or 4.36, but I used 4.2] Lightyears (lightyear = 1 year of travel at So L?, or 9,454,254,955,488,000 meters) distance in meters to AC: 39,707,870,813,049,600 meters

to:

SOL: 299,792,458 m/s (meters per second) (AKA a Lightsecond, as heard on Andromeda) 1/4 SOL: 74,948,114.5 m/s distance to Alpha Centauri: 4.2 [or 4.36, but I used 4.2] Lightyears (lightyear = 1 year of travel at SOL)

Changed lines 11-12 from:

(distance traveled @)So L?: 9,454,254,955,488,000 m/y (meters per year) AT So L?: 4.2 years

to:

Distance to AC: 39,707,870,813,049,600 meters

Changed lines 13-14 from:

1/4 So L?: 2,363,563,738,872,000 m/y AT 1/4 So L?: 16.8 years

to:

(distance traveled @)SOL: 9,454,254,955,488,000 m/y (meters per year) AT SOL: 4.2 years

1/4 SOL: 2,363,563,738,872,000 m/y AT 1/4 SOL: 16.8 years

May 28, 2005, at 01:18 AM MST by MikeChance -
Changed line 3 from:

If we had mastered a drive able to safely accelerate ships to one quarter the speed of light (So L?), it wouldn't take that long to get to Alpha Centauri. Especially in ext. hibernation. BTW, when I say distance, I mean estimated... And, this is only an example made to point out the ease with which earth's population could leave and arrive somewhere easily... also, imagine if they headed for a star cluster... where the entire cluster is no more than 10 or 20 lightyears across... a "minigalaxy"... you could start with one system and there'd be many more within 1 or 2 lightyears. earth is in the boondocks. So, don't bash me on the incorrect reporting of the distance to Alpha Centauri... it was only an example... and anyway, .15 LY is NOTHING.

to:

If we had mastered a drive able to safely accelerate ships to one quarter the speed of light(or So L?), it wouldn't take that long to get to Alpha Centauri. Especially in ext. hibernation. BTW, when I say distance, I mean estimated... And, this is only an example made to point out the ease with which earth's population could leave and arrive somewhere easily... also, imagine if they headed for a star cluster... where the entire cluster is no more than 10 or 20 lightyears across... a "minigalaxy"... you could start with one system and there'd be many more within 1 or 2 lightyears. earth is in the boondocks. So, don't bash me on the incorrect reporting of the distance to Alpha Centauri... it was only an example... and anyway, .15 LY is NOTHING.

May 28, 2005, at 01:18 AM MST by MikeChance -
Added lines 1-2:

Mike Chance?'s Theory:

Changed lines 34-37 from:

AT Mach 100: 37,001.6(decimals truncated) years

to:

AT Mach 100: 37,001.6(decimals truncated) years

Now, I've no idea what affect Time Dilation would have on this, but I beleive it stands as a good theory as to the size of the Firefly Universe, and how we got there...

May 28, 2005, at 01:15 AM MST by MikeChance -
Changed lines 1-32 from:

Describe MC Theory here.

to:

If we had mastered a drive able to safely accelerate ships to one quarter the speed of light (So L?), it wouldn't take that long to get to Alpha Centauri. Especially in ext. hibernation. BTW, when I say distance, I mean estimated... And, this is only an example made to point out the ease with which earth's population could leave and arrive somewhere easily... also, imagine if they headed for a star cluster... where the entire cluster is no more than 10 or 20 lightyears across... a "minigalaxy"... you could start with one system and there'd be many more within 1 or 2 lightyears. earth is in the boondocks. So, don't bash me on the incorrect reporting of the distance to Alpha Centauri... it was only an example... and anyway, .15 LY is NOTHING.

REMEMBER, I USED METERS. NOT MILES. 1 Meter is equal to ABOUT 3.1 feet...

So L?: 299,792,458 m/s (meters per second) (AKA a Lightsecond, as heard on Andromeda) 1/4 So L?: 74,948,114.5 m/s distance to Alpha Centauri: 4.2[or 4.36, but I used 4.2] Lightyears (lightyear = 1 year of travel at So L?, or 9,454,254,955,488,000 meters) distance in meters to AC: 39,707,870,813,049,600 meters

(distance traveled @)So L?: 9,454,254,955,488,000 m/y (meters per year) AT So L?: 4.2 years

1/4 So L?: 2,363,563,738,872,000 m/y AT 1/4 So L?: 16.8 years

FOR COMPARISON, the speed of sound at Sea Level (yes, it's different at different altitudes): speed of sound: 340.29 m/s (AKA MACH 1?)

MACH 1: 10,731,385,440 meters AT Mach 1(speed of sound): 3,700,162.5(decimals truncated) years

MACH 10: 107,313,854,400 m/y AT Mach 10: 370,016.2(decimals truncated) years

MACH 20: 214,627,708,800 m/y AT Mach 20: 185,008.1(decimals truncated) years

MACH 30: 321,941,563,200 m/y AT Mach 30: 123,338.7(decimals truncated) years

MACH 100: 1,073,138,544,000 m/y AT Mach 100: 37,001.6(decimals truncated) years

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Page last modified on September 30, 2006, at 09:42 AM MST